International Journal of Computational Intelligence Systems

Volume 14, Issue 1, 2021, Pages 1923 - 1933

Interior BCK/BCI-Algebras

Authors
Sun Shin Ahn1, ORCID, Hashem Bordbar2, *, ORCID, Young Bae Jun3, ORCID
1Department of Mathematics Education, Dongguk University, Seoul, 04620, Korea
2Center for Information Technologies and Applied Mathematics, University of Nova Gorica, Nova Gorica, 5000, Slovenia
3Department of Mathematics Education, Gyeongsang National University, Jinju, 52828, Korea
*Corresponding author. Email: hashem.bordbar@ung.si
Corresponding Author
Hashem Bordbar
Received 18 December 2020, Accepted 6 June 2021, Available Online 1 July 2021.
DOI
10.2991/ijcis.d.210622.002How to use a DOI?
Keywords
Interior BCK/BCI-algebras; Positive implicative interior BCK-algebras; (weak) interior ideals; Positive implicative interior ideals; Positive implicative weak interior ideal of type 1, type 2, and type 3
Abstract

The notions of interior BCK/BCI-algebras, positive implicative interior BCK-algebras, (weak) interior ideals, positive implicative interior ideals, a positive implicative weak interior ideal of type 1, type 2, and type 3 are introduced, and related properties are investigated. A mapping is provided to the set of all involutions of a bounded BCK-algebra in relation to any interior BCK-algebra so that the set of all involutions of a bounded BCK-algebra can be an interior BCK-algebra. The relationship between interior ideals, weak interior ideals, and positive implicative interior ideals is established. The conditions under which a weak interior ideal can change to an interior ideal are founded. The conditions for an interior ideal to be a positive implicative interior ideal are provided. The scalability for a positive implicative interior ideal is discussed. The relationship between type 1, type 2, and type 3 on positive implicative weak interior ideals are investigated. The relationship between weak interior ideal and positive implicative weak interior ideal of type 1, type 2, and type 3 are established.

Copyright
© 2021 The Authors. Published by Atlantis Press B.V.
Open Access
This is an open access article distributed under the CC BY-NC 4.0 license (http://creativecommons.org/licenses/by-nc/4.0/).

1. INTRODUCTION

Interior operators are mainly dealt with in topology and category theory. The notion of an interior operator in an arbitrary category was formally introduced by Vorster [1], and it was successfully used in [2,3] to study notions of connectedness and disconnectedness in topology. Sgro presented a model theory of the interior operator on product topologies with continuous functions (see [4]). An interior algebra is a certain type of algebraic structure that encodes the idea of the topological interior of a set. Interior algebras are to topology and modal logic.

In this article, we introduce the notions of interior BCK/BCI-algebras, positive implicative interior BCK-algebras, (weak) interior ideals, positive implicative interior ideals, a positive implicative weak interior ideal of type 1, type 2, and type 3. We present examples that support these notions and look at the relevant properties. Using the set of all interior BCK/BCI-algebras, we make a BCK/BCI-algebra. We suggest the conditions under which the composition of two interior BCK/BCI-algebras can be an interior BCK/BCI-algebra. We provide a mapping to the set of all involutions of a bounded BCK-algebra in relation to any interior BCK-algebra so that the set of all involutions of a bounded BCK-algebra can be an interior BCK-algebra. We show that the intersection of all (weak) interior ideals in an interior BCK/BCI-algebra is also a (weak) interior ideal in the same interior BCK/BCI-algebra. We discuss the relationship between interior ideals, weak interior ideals, and positive implicative interior ideals. We look for conditions under which a weak interior ideal can be an interior ideal. We provide conditions under which an interior ideal can be a positive implicative interior ideal. We discuss the scalability for a positive implicative interior ideal. We consider the relationship between type 1, type 2, and type 3 on positive implicative weak interior ideals. We establish the relationship between weak interior ideal and positive implicative weak interior ideal of type 1, type 2, and type 3.

As far as the authors know, this is the first article that investigates the interior operations in BCK/BCI-algebras.

2. PRELIMINARIES

A BCK/BCI-algebra is an important class of logical algebras introduced by K. Iséki (see [5,6]) and was extensively investigated by several researchers. Please refer to [713]

We recall the definitions and basic results required in this paper. See the books [14,15] for further information regarding BCK/BCI-algebras.

If a set X has a special element 0 and a binary operation ∗ satisfying the conditions:

  1. (u,v,wX)(((uv)(uw))(wv)=0),

  2. (u,vX)((u(uv))v=0),

  3. (uX)(uu=0),

  4. (u,vX)(uv=0,vu=0u=v),

    then we say that BCI-algebra is a X. If a BCI-algebra X satisfies the following identity:

  5. (uX)(0u=0),

    then X is called a BCK-algebra.

The order relation “” in a BCK/BCI-algebra X is defined as follows:

(x,yX)(xyxy=0).(1)

Every BCK/BCI-algebra X satisfies the following conditions:

(uX)(u0=u),(2)
(u,v,wX)(uvuwvw,wvwu),(3)
(u,v,wX)((uv)w=(uw)v)(4)
where uv if and only if uv=0.

A BCK-algebra X is said to be

  • bounded (see [15]) if there exist an element 1 in X such that x1 for all xX. In a bounded BCK-algebra X, we denote 1x by ¬x.

  • positive implicative (see [15]) if it satisfies

    (x,y,zX)((xz)(yz)=(xy)z).(5)

Every bounded BCK-algebra X satisfies

(x,yX)(xy¬y¬x),(6)
(xX)(¬¬¬x=¬x).(7)

If an element x of a bounded BCK-algebra X satisfies ¬¬x=x., then x is called an involution of X (see [15]). The set of all involutions of a bounded BCK-algebra X is denoted by Iv(X). Note that if X is a bounded BCK-algebra, then Iv(X) is a bounded subalgebra of X.

A nonempty subset S of a BCK/BCI-algebra X is called a subalgebra of X (see [15]) if xyS for all x,yS. A subset S of a BCK/BCI-algebra X is called an ideal of X (see [15]) if it satisfies

0A,(8)
(xX)(yA)(xyAxA).(9)

Every ideal A of a BCK/BCI-algebra X satisfies the next assertion.

(x,yX)(xy,yAxA).(10)

A subset A of a BCK-algebra X is called a positive implicative ideal of X (see [15]) if it satisfies (8) and

(u,v,wX)((uv)wA,vwAuwA).(11)

3. INTERIOR BCK/BCI-ALGEBRAS

Definition 3.1.

An interior BCK/BCI-algebra is defined to be a pair (X,) in which X is a BCK/BCI-algebra and l is a self-map on X such that

(xX)((x)x),(12)
(xX)(2(x)=(x)),(13)
(x,yX)(xy(x)(y)).(14)

Example 3.2

If X is a BCK/BCI-algebra, then is an interior BCK/BCI-algebra where (X,i) is the identity self-map on X.

Example 3.3

Consider a BCK-algebra X={0,1,2,3,4} with the following Cayley table.

01234000000110000222002333203444440

Define a mapping :XX by (0)=0,(1)=1,(2)=1,(3)=1 and (4)=4. Then (X,) is an interior BCK-algebra.

Example 3.4

Consider a BCK-algebra X={0,1,2,3,4} with the following Cayley table.

01234000000110100222000332100444440

Then X is bounded BCK-algebra with 4 as a greatest element. If we define a mapping :XX by (0)=0,(1)=1,(2)=0,(3)=1(4)=4, then (X,) is an interior BCK-algebra. If we define a mapping ȷ:XX by ȷ(0)=0,ȷ(1)=1,ȷ(2)=2,ȷ(3)=0 and ȷ(4)=4, then (X,ȷ) is not an interior BCK-algebra since 23 and (2)ȷ(3).

Given a BCK/BCI-algebra X, let (X) be the set of all interior BCK/BCI-algebras, that is, (X)={(X,i)i is a self-map on X that satisfies conditions (12), (13) and (14)}.

We consider a binary operation on (X) as follows:

((X,i),(X,j)(X))((X,i)(X,j)=(X,ij))(15)
in which (ij)(x)=i(x)j(x) for all xX.

Theorem 3.5.

If X is a BCK/BCI-algebra, then ((X),,(X,0)) is a BCK/BCI-algebra where 0(x)=0 for all xX.

Proof.

It is straightforward.

The following example describes Theorem 3.5.

Example 3.6

Consider a BCK-algebra X={0,1,2,3} with the following Cayley table.

012300000110002220233330

The set of all interior BCK/BCI-algebras is (X)={(X,0),(X,1),,(X,7)} where the self-maps 0,1,,7 are given by the Table 1.

x 0 1 2 3
0(x) 0 0 0 0
1(x) 0 0 0 3
2(x) 0 0 2 0
3(x) 0 0 2 3
4(x) 0 1 1 1
5(x) 0 1 2 1
6(x) 0 1 1 3
7(x) 0 1 2 3
Table 1

Table for the self-maps 0,1,,7.

By routine verification we can check that ((X),,(X,0)) is a BCK/BCI-algebra.

Question 3.7.

If (X,) and (X,ȷ) are interior BCK/BCI-algebras, then

  1. Is the composition of (X,) and (X,ȷ) an interior BCK/BCI-algebra?

  2. Is ȷ=ȷ?

    We look at the example below to see that the answer to the above question is negative.

Example 3.8

Let X be the BCK-algebra and (X,) be the interior BCK-algebra in Example 3.3. Let ȷ be the self-map on X which is defined by ȷ(0)=0,ȷ(1)=0,ȷ(2)=2,ȷ(3)=2 and ȷ(4)=4. Then (X,ȷ) is an interior BCK-algebra. The compositions ȷ and ȷ of and ȷ are given by Table 2.

x 0 1 2 3 4
(ȷ)(x) 0 0 1 1 4
(ȷ)(x) 0 0 0 0 4
Table 2

Table for the compositions ȷ and ȷ.

Then (X,ȷ) is an interior BCK-algebra, but (X,ȷ) is not an interior BCK-algebra since (ȷ)2(2)=(ȷ)(1)=01=(ȷ)(2). According to Table 2, ȷȷ can be immediately identified.

Example 3.9

Consider a BCI-algebra X={0,1,2,a,b} with the following Cayley table.

012ab0000aa1100aa2220baaaaa00bbba20

Let and ȷ be self-maps on X defined by (0)=(1)=0,(2)=2,(a)=a and (b)=a, while ȷ(0)=0,ȷ(1)=ȷ(2)=1,ȷ(a)=a and ȷ(b)=b. Then (X,) and (X,ȷ) are interior BCI-algebras. The compositions ȷ and ȷ of and ȷ are given by Table 3.

x 0 1 2 a b
(ȷ)(x) 0 0 0 a a
(ȷ)(x) 0 0 1 a a
Table 3

Table for the compositions ȷ and ȷ.

Then (X,ȷ) is an interior BCI-algebra, but (X,ȷ) is not an interior BCI-algebra since (ȷ)2(2)=(ȷ)(1)=01=(ȷ)(2). According to Table 3, ȷȷ can be immediately identified.

We suggest the conditions under which the composition of two interior BCK/BCI-algebras can be an interior BCK/BCI-algebra.

Theorem 3.10.

If (X,) and (X,ȷ) are interior BCK/BCI-algebras such that ȷ=ȷ, then (X,ȷ) is an interior BCK/BCI-algebra.

Proof.

Assume that ȷ=ȷ. Using (12), we have (ȷ)(x)=(ȷ(x))ȷ(x)x for all xX, and so ȷ satisfies the condition (12). Also,

(ȷ)2(x)=((ȷ)(ȷ))(x)=(()(ȷȷ))(x)=()((ȷȷ)(x))=()(ȷ(x))=(ȷ(x))=(ȷ)(x)
for all xX, which shows that ȷ satisfies the condition (13). For every x,yX, if xy then ȷ(x)ȷ(y), and so (ȷ)(x)=(ȷ(x))(ȷ(y))=(ȷ)(y). Therefore (X,ȷ) is an interior BCK/BCI-algebra.

Given interior BCK/BCI-algebras (X,) and (X,ȷ), we define

ȷ(xX)((x)ȷ(x)).(16)

Given a self-map on X, the set

():={xX(x)=x}
is called the identity part of in X, and the set
ker():={xX(x)=0}
is called the kernel of .

Proposition 3.11.

If (X,) and (X,ȷ) are interior BCK/BCI-algebras, then

  1. ȷȷ=,

  2. I()=I(ȷ)=ȷ.

Proof.

  1. If ȷ, then (x)ȷ(x) for all xX, and so (x)=2(x)(ȷ)(x). Also (ȷ)(x)=(ȷ(x))ȷ(ȷ(x))=ȷ(x)x which implies that (ȷ)(x)=(ȷ(x))=((ȷ(x)))(x). Hence (ȷ)(x)=(x) for all xX. Therefore ȷ=. Conversely, assume that ȷ=. Then (x)=(ȷ)(x)ȷ(x) for all xX. Thus ȷ.

  2. It is clear that if =ȷ, then I()=I(ȷ). Suppose that I()=I(ȷ). The condition (13) induces (x)I()=I(ȷ), and so ȷ((x))=(x) for all xX. Hence ȷ=. Similarly ȷ=ȷ. Using (12) and (14), we have (x)=(ȷ)(x)ȷ(x) and ȷ(x)=(ȷ)(x)(x). Thus (x)=ȷ(x) for all xX. Therefore =ȷ.

Proposition 3.12.

If (X,) is an interior BCK/BCI-algebra, then

  1. (x)yx(y),

  2. (xy)x(y),

for all x,yX.

Proof.

Let x,yX. Using (12) and (3), we have (x)y(x)(y)x(y) which proves (i). Since (xy)xy and (y)y, it follows from (3) that (xy)xyx(y). Hence (ii) is valid.

Proposition 3.13.

If (X,) is an interior BCK-algebra, then

  1. (0)=0. This is also true in an interior BCI-algebra (X,),

  2. ((x(xy))(yx))(x(x(y(yx)))),

  3. (xy)(z)(x(z))y

    for all x,yX. Moreover, if X is bounded, then

  4. (¬x)¬(x),

  5. (¬x¬y)yx,

    for all x,yX.

Proof.

  1. Using (12), we have (0)0, and so (0)=(0)0=0 by (2).

  2. For every x,y,zX, we have

    ((x(xy))(yx))(x(x+(y(yx))))=((x(xy))(x(x(y(yx)))))(yx)=((x(x(x(y(yx)))))(xy))(yx)=((x(y(yx)))(xy))(yx)(y(y(yx)))(yx)=(y(yx))(y(yx))=0
    by (I), (III) and (4). Since 0x for all xX, it follows from (IV) that
    ((x(xy))(yx))(x(x+(y(yx))))=0,
    i.e., (x(xy))(yx)x(x(y(yx))). Hence ((x(xy))(yx))(x(x(y(yx)))) for all x,y,zX by (14).

  3. Let x,y,zX. Using (3), (4) and (12), we have

    (xy)(z)(xy)(z)=(x(z))y.

    Assume that X is bounded. If we put x=1 and y=x in Proposition 3.12(ii), then (¬x)=  (1x)1(x)=¬(x) for all xX. Hence (iv) is valid.

  4. If we take u=1,v=x and w=y in (I), then ¬x¬y=(1x)(1y)yx. It follows from (12) that (¬x¬y)¬x¬yyx.

Theorem 3.14.

If (X,) is an interior BCK-algebra, then (Iv(X),˜) is an interior BCK-algebra where ˜ is a self-map on Iυ(X) which is defined by ˜(x)=¬¬(x) for all xIυ(X).

Proof.

Let xIυ(X). Since (x)x, it follows from (6) that

˜(x)=¬¬(x)¬¬x=x,
that is, ˜ satisfies the condition (12). For every xIυ(X), we have
˜2(x)=˜(¬¬(x))=¬¬¬¬(x)=¬¬(x)=˜(x)
by (7). Hence ˜ satisfies the condition (13). Let x,yIυ(X) be such that xy. Then (x)(y) by (14), and so
˜(x)=¬¬(x)¬¬(y)=˜(y)
by (6). This shows that ˜ satisfies the condition (14).

Question 3.15.

If (X,) is an interior BCK-algebra, will the following items be established?

(x,y,zX)(xyz(xz)(yz)).(17)
(x,yX)(xyy(xy)=(0).(18)
(x,yX)(((xy)y)=(xy)=((xy)(x(xy)))).(19)
(x,y,zX)(((xy)z)=((xz)(yz))).(20)

The following example shows that the answer to the above question is negative.

Example 3.16

Consider a BCK-algebra X={0,1,2,3,4} with the following Cayley table.

01234000000110001221012331103444440

Define a mapping :XX by (0)=(4)=0,(1)=(2)=1 and (3)=3. Then (X,) is an interior BCK-algebra. For elements 2,3X, we have 23=13. But (23)=(1)=10=(0)=(33) and (23)(0). Hence (17) and (18) are not true in general. Since ((32)2)=0=((32)(3(32)) and (32)=1, we know that (19) is not true. The equality (20) is not true since

((21)3)=(0)=01=(1)=((23)(1+3)).

Definition 3.17.

An interior BCK-algebra (X,) is said to be positive implicative if the condition (20) is established.

Example 3.18

Consider a BCK-algebra X={0,1,2,3,4} with the following Cayley table.

01234000000110100222002332102444440

Define a mapping :XX by (0)=(2)=0,(1)=(4)=1 and (3)=3. Then (X,) is a positive implicative interior BCK-algebra.

Theorem 3.19.

If (X,) is a positive implicative BCK-algebra, then the interior BCK-algebra (X,) is positive implicative.

Proof.

It is straightforward.

In the following example, we can see that the converse of Theorem 3.19 is not established.

Example 3.20

Consider a BCK-algebra X={0,1,2,3,4} with the following Cayley table.

012300000110012210233330

Let be a self-map on X defined by (0)=(1)=0,(2)=2 and (3)=3. Then (X,) is a positive implicative interior BCK-algebra while X is not a positive implicative BCK-algebra since (21)1(21)(11).

Proposition 3.21.

If (X,) is a positive implicative interior BCK-algebra, then the conditions (17), (18), (19) and (20) are established.

Proof.

Assume that (X,) is a positive implicative interior BCK-algebra. Let x,y,zX be such that xyz. Then (xz)(yz)=0, i.e., xzyz since X is a positive implicative BCK-algebra. It follows from (14) that (xz)(yz). Hence (17) is valid. Let x,yX be such that xyy. Then xy=(xy)(yy)=0 by (III), (2) and (5). Hence (xy)=(0), and so (18) holds. Since X is a positive implicative BCK-algebra, we have xy=(xy)y=(xy)(x(xy)) for all x,yX. Hence (xy)=((xy)y)=((xy)(x(xy))), i.e., (19) is true. It is clear that (20) is valid.

4. INTERIOR IDEALS IN INTERIOR BCK/BCI-ALGEBRAS

Definition 4.1.

Let (X,) be an interior BCK/BCI-algebra. Then a subset A of X is called an interior ideal in (X,) if A is an ideal of X which satisfies the following assertion:

(xX)((x)AxA).(21)

It is clear that {0} and X are interior ideals in every interior BCK/BCI-algebra (X,).

Example 4.2

  1. Consider the interior BCK-algebra (X,) in Example 3.16. Then A:={0,4} is an interior ideal in B:={0,1,2,3}, and (X,) is an ideal of X which is not an interior ideal in (X,ȷ) since (4)=0B but 4B.

  2. Consider the interior BCI-algebra (X,) in Example 3.16. Then A:={0,1,2} is an interior ideal in (X,) and B:={0,1} is an ideal of (X,ȷ) which is not an interior ideal in X since ȷ(2)=1B but 2B.

Theorem 4.3.

The intersection of all interior ideals in an interior BCK/BCI-algebra (X,) is also an interior ideal in (X,).

Proof.

Let {AiiΛ} be the set of all interior ideals in an interior BCK/BCI-algebra (X,). It is clear that iΛAi is an ideal of X. Let xX be such that (x)iΛAi. Then (x)Ai for all iΛ. Since Ai is an interior ideal in (X,) for all iΛ, it follows from (21) that xAi for all iΛ. Therefore xiΛAi, and so iΛAi is an interior ideal in (X,).

In the following example, we know that the union of interior ideals in an interior BCK/BCI-algebra (X,) may not be an interior ideal in (X,).

Example 4.4

Consider the BCK-algebra X={0,1,2,3,4} in Example 3.18. Let be a self-map on X given by (0)=0,(1)=(4)=1,(2)=2 and (3)=3. Then (X,) is an interior BCK-algebra. Put A:={0,1,4} and B:={0,2}. By routine verification we can check that A and B are interior ideals in (X,). Since the union AB={0,1,2,4} of A and B is not an ideal of X, and so it can't be an interior ideal in (X,).

Definition 4.5.

Let (X,) be an interior BCK/BCI-algebra. Then a subset A of X is called a weak interior ideal in (X,) if it satisfies (8) and

(x,yX)((x)yA,(y)AxA).(22)

Example 4.6

Consider a BCK-algebra X={0,1,2,3,4} with the following Cayley table.

01234000000110110222020333303444440

Let be a self-map on X given by (0)=(2)=0,(1)=(4)=1 and (3)=3. Then (X,) is an interior BCK-algebra and A:={0,2,4} is a weak interior ideal in (X,).

Example 4.7

Consider a BCI-algebra X={0,1,2,a,b} with the following Cayley table.

012ab0000ba1100ba2210baaaaa0bbbbba0

Define a mapping :XX by (0)=0,(1)=(2)=1,(a)=a and (b)=b. Then (X,) is an interior BCI-algebra and A:={0,1,2} is a weak interior ideal in (X,).

Note that the interior A:={0,1,2} of (X,) in Example 4.7 is an ideal of X. But the interior A:={0,2,4} of (X,) in Example 4.6 is not an ideal of X. This shows that any weak interior ideal in an interior BCK/BCI-algebra (X,) may not be an ideal of X in general.

Theorem 4.8.

The intersection of all weak interior ideals in an interior BCK/BCI-algebra (X,) is also a weak interior ideal in (X,).

Proof.

Let {AiiΛ} be the set of all weak interior ideals in an interior BCK/BCI-algebra (X,). It is clear that 0iΛAi. Let x,yX be such that (x)yiΛAi and (y)iΛAi.

Then (x)yAi and (y)Ai for all iΛ. Since Ai is a weak interior ideal in (X,) for all iΛ, it follows from (22) that xAi for all iΛ. Hence xiΛAi, and therefore iΛAi is a weak interior ideal in (X,).

In the following example, we know that the union of weak interior ideals in an interior BCK/BCI-algebra (X,) may not be a weak interior ideal in (X,).

Example 4.9

Consider the BCK-algebra X={0,1,2,3,4} in Example 3.18. Let be a self-map on X given by (0)=0,(1)=(4)=1,(2)=2 and (3)=3. Then (X,) is an interior BCK-algebra. Routine calculations show that A1 := {0,2} and A2:={0,1,4} are weak interior ideals in (X,). But the union A1A2={0,1,2,4} is not a weak interior ideal in (X,) since (3)2=32=1A1A2 and (2)=2A1A2, but 3A1A2.

Theorem 4.10.

In an interior BCK/BCI-algebra (X,), every interior ideal is a weak interior ideal.

Proof.

Let A be an interior ideal in an interior BCK/BCI-algebra (X,). Let x,yX be such that (x)yA and (y)A. Then yA by (21). Using (9), we have (x)A which implies from (21) that xA. Therefore A is a weak interior ideal in (X,).

The following example shows that the converse of Theorem 4.10 is not established.

Example 4.11

Consider the weak interior ideal A in Example 4.6. Then A is not an ideal of X since 14A and 4A but 1A. Hence A is not an interior ideal.

In the following theorem, we present a condition under which the converse of Theorem 4.10 can be established in an interior BCK-algebra.

Theorem 4.12.

If A is a weak interior ideal in an interior BCK/BCI-algebra (X,) which is also an ideal of X, then A is an interior ideal in (X,).

Proof.

Let A be a weak interior ideal in an interior BCK/BCI-algebra (X,) which is also an ideal of X. Let xX be such that (x)A. Then (x)0=(x)A and (0)=0A. It follows from (22) that xA. Therefore A is an interior ideal in (X,).

Let (X,) be an interior BCK-algebra. Given a nonempty subset L of X, the interior ideal in (X,) generated by L is defined to be the smallest interior ideal in (X,) containing L, and it is denoted by L.

Example 4.13

Consider a BCK-algebra X={0,1,2,3,4} with the following Cayley table:

01234000000110101222020333303444440

Define a mapping :XX by (0)=0,(1)=(3)=1 and (2)=(4)=2. Then (X,) is an interior BCK-algebra and all interior ideals are A0={0},A1={0,1},A2={0,2},A3={0,1,3},A4={0,2,4} and A5=X. If we take L={0,3}, then the interior ideal in (X,) generated by L is L={0,1,3}.

We present a question about the interior ideal generated by a set as follows:

Question 4.14.

How is the interior ideal generated by subset of an interior BCK-algebra described?

Definition 4.15.

Let (X,) be an interior BCK-algebra. Then a subset A of X is called a positive implicative interior ideal in (X,) if A is a positive implicative ideal of X which satisfies the condition (21).

Example 4.16

Let X be the BCK-algebra in Example 3.3 and let be a self-map on X given by (0)=0,(1)=(4)=1 and (2)=(3)=2. Then (X,) is an interior BCK-algebra and the set A := {0,1,3} is a positive implicative interior ideal in (X,). The set B := {0,1,4} is an interior ideal in (X,), but it is not a positive implicative interior ideal in (X,) since it is not a positive implicative ideal of X.

Theorem 4.17.

In an interior BCK-algebra (X,), every positive implicative interior ideal is an interior ideal.

Proof.

It is straightforward because every positive implicative ideal is an ideal in a BCK-algebra.

In general, the converse of Theorem 4.17 is not true in general as seen in Example 4.16. So we need to find condition(s) for an interior ideal to be a positive implicative interior ideal.

Given an ideal A and an element w in an interior BCK-algebra (X,), consider the set

Aw:={xXxwA}.(23)

It is clear that 0Aw. The following example shows that Aw is neither an interior ideal nor a weak interior ideal.

Example 4.18

Consider a BCK-algebra X={0,1,2,3,4} with the following Cayley table:

01234000000110101222020331303444440

Define a mapping :XX by (0)=0,(1)=(3)=1 and (2)=(4)=2. Then (X,) is an interior BCK-algebra and A={0,2} is an ideal of X. If we take w=1, then Aw={0,1,2} which is not an ideal of X. Also, Aw does not satisfy (21) since (4)=2Aw but 4Aw. Hence Aw is not an interior ideal in (X,). Since (3)1=0Aw and (1)=1Aw but 3Aw, we know that Aw is not a weak interior ideal in (X,).

Question 4.19.

Under what conditions can the set Aw be a (weak) interior ideal in (X,)?

We consider conditions for an interior ideal to be a positive implicative interior ideal in an interior BCK-algebra.

Theorem 4.20.

Let A be an interior ideal in an interior BCK-algebra (X,) and suppose that Aw is an ideal of X for all wX. Then A is a positive implicative interior ideal in (X,).

Proof.

It is sufficient to show that A is a positive implicative ideal of X. Let x,y,zX be such that (xy)zA and yzA. Then xyAz and yAz. Since Az is an ideal of X, we have xAz and so xzA. This shows that A is a positive implicative ideal of X, and hence A is a positive implicative interior ideal in (X,).

Given a subset A and an element w in an interior BCK-algebra (X,), we present conditions for the set Aw to be an interior ideal.

Theorem 4.21.

If A is a positive implicative interior ideal in an interior BCK-algebra (X,) such that

(uX)(2(u)=u),(24)
(u,vX)(uv,uAvA),(25)
(uX)(uA(u)A),(26)
then Aw is an interior ideal in (X,) for wX.

Proof.

Let x,yX be such that xyAw and yAw. Then (xy)wA and ywA. Since A is a positive implicative ideal of X, it follows that xwA, that is, xAw. Hence Aw is an ideal of X. Let xX be such that (x)Aw. Then (x)wA, and so ((x)w)A by (26). Using Proposition 3.12 and (24), we have

((x)w)(x)(w)x2(w)=xw.

It follows from (25) that xwA, that is, xAw. Therefore Aw is an interior ideal in (X,) for wX.

Theorem 4.22.

Let A be a subset of X in an interior BCK-algebra (X,) satisfying the condition (21) and

0A,(27)
(x,yX)(zA)((xy)yAzxyA),(28)
then A is a positive implicative interior ideal in (X,).

Proof.

Let x,yA be such that xyA and yA. Then (x0)0=xAy, and so x=x0A by (28). Hence A is an interior ideal in (X,). Let x,y,zX be such that (xy)zA and yzA. Note that ((xz)z)(yz)(xz)y=(xy)zA. Since A is an ideal of X, it follows that (xz)zA0. Hence xzA by (28). Therefore A is a positive implicative interior ideal in (X,).

In the following theorem, we discuss the scalability for positive implicative interior ideal.

Theorem 4.23.

Let A and B be interior ideals in an interior BCK-algebra (X,). If A is contained in B and A is a positive implicative interior ideal in (X,), then so is B.

Proof.

Assume that (xy)zB for all x,y,zX. Then

((x((xy)z))y)z=((xyz)((xy)z)=0A.

Note that

(((x((xy)z))(yz))z)z=(((x((xy)z))z)(yz))z((x((xy)z))y)z.

Hence (((x((xy)z))(yz))z)zA. Since A is a positive implicative ideal of X, it follows that

((xz)(yz))((xy)z)=((x((xy)z))z)(yz)=((x((xy)z))(yz))zAB.

Thus (xz)(yz)B since B is an ideal of X. Assume that (xy)yBz for zB. Then ((xz)y)yB, which implies that (xy)z=((xz)y)(yy)B. Since zB and B is an ideal of X, it follows that xyB. Therefore B is a positive implicative interior ideal in (X,) by Theorem 4.22.

Definition 4.24.

Let (X,) be an interior BCK-algebra and let A be a subset of X which satisfies (8). Then A is called

  • a positive implicative weak interior ideal of type 1 in (X,) if it satisfies

    (x,y,zX)(((x)y)zA,(yz)AxzA).(29)

  • a positive implicative weak interior ideal of type 2 in (X,) if it satisfies

    (x,y,zX)(((xy)zA,(yz)Ax(z)A).(30)

  • a positive implicative weak interior ideal of type 3 in (X,) if it satisfies

    (x,y,zX)(((x)y)zA,(yz)A(x)zA).(31)

Example 4.25

Consider the BCK-algebra X in Example 3.20. Define a mapping :XX by (0)=(1)=0,(2)=2 and (3)=3. Then (X,) is an interior BCK-algebra and A:={0,1,2} is a positive implicative weak interior ideal of type 1 in (X,).

Example 4.26

Consider a BCK-algebra X={0,1,2,3,4} with the following Cayley table:

01234000000110000221000333303444440

Define a mapping :XX by (0)=0,(1)=(2)=1,(3)=3 and (4)=4. Then (X,) is an interior BCK-algebra and A := {0,1,2} is a positive implicative weak interior ideal of type 2 in (X,).

Example 4.27

Consider a BCK-algebra X={0,1,2,3,4} with the following Cayley table:

01234000000110101222020331303444440

Define a mapping :XX by (0)=(1)=(3)=0 and (2)=(4)=2. Then (X,) is an interior BCK-algebra and A:={0,2} is a positive implicative weak interior ideal of type 3 in (X,).

It is generally well known that every positive implicative ideal is an ideal in BCK-algebras. In considering the relationship between a positive implicative weak interior ideal of type 1 (respectivley, type 2 and type 3) and an ideal, we pose the following question:

Question 4.28.

In an interior BCK-algebra (X,), if A is a positive implicative weak interior ideal of type 1 (respectivley, type 2 and type 3) in (X,), then is A an ideal of A?

The answer to the Question 4.28 is negative as shown in the following example:

Example 4.29

Consider a BCK-algebra X={0,1,2,3,4} with the following Cayley table:

012000011002220

Define a mapping :XX by (0)=0 and (1)=(2)=1. Then (X,) is an interior BCK-algebra and A:={0,2} is a positive implicative weak interior ideal of type 1 and type 2 in (X,) which is not an ideal of X. Let (X,) be an interior BCK-algebra in Example 4.27. Then A={0,1,2} is a positive implicative weak interior ideal of type 3 which is not an ideal of X.

We discuss relationship between type 1, type 2, and type 3 on positive implicative weak interior ideal.

Theorem 4.30.

In an interior BCK-algebra X, every positive implicative weak interior ideal A of type 2 which satisfies the condition (9) is a positive implicative weak interior ideal of type 1.

Proof.

Let A be a positive implicative weak interior ideal of type 2 which satisfies the condition (9) in an interior BCK-algebra (X,). Let x,y,zX be such that ((x)y)zA and (yz)A. Then x(z)A by (30). Using (12) and (3), we have xzx(z). It follows from (10) that xzA. Hence A is a positive implicative weak interior ideal of type 1.

The following example shows that any positive implicative weak interior ideal of type 1 is not a positive implicative weak interior ideal of type 2.

Example 4.31

Consider a BCK-algebra X={0,1,2,3,4} with the following Cayley table:

01234000000110100222000331303444440

Define a mapping :XX by (0)=0,(1)=1,(2)=(3)=2 and (4)=4. Then (X,) is an interior BCK-algebra and A:={0,3} is a positive implicative weak interior ideal oftype 1 in (X,) but it is not a positive implicative weak interior ideal of type 2 since ((1)0)3=0A and (03)=0A but 1(3)=12=1A.

Theorem 4.32.

In an interior BCK-algebra X, every positive implicative weak interior ideal A of type 1 which satisfies the condition (9) is a positive implicative weak interior ideal of type 3.

Proof.

Let A be a positive implicative weak interior ideal of type 1 which satisfies the condition (9) in an interior BCK-algebra (X,). Let x,y,zX be such that ((x)y)zA and (yz)A. Then xzA by (29). Using (12) and (3), we have (x)zxz. It follows from (10) that (x)zA. Hence A is a positive implicative weak interior ideal of type 3.

The following example shows that any positive implicative weak interior ideal of type 3 is not a positive implicative weak interior ideal of type 1:

Example 4.33

Consider a BCK-algebra X={0,1,2,3} with the following Cayley table:

012300000110012210233330

Define a mapping :XX by (0)=0,(1)=(2)=1 and (3)=0. Then (X,) is an interior BCK-algebra and A:={0,1,2} is a positive implicative weak interior ideal of type 3 in (X,) but it is not a positive implicative weak interior ideal of type 1 since ((3)3)0=0A and (30)=0A but 30=3A.

Corollary 4.34.

In an interior BCK-algebra X, every positive implicative weak interior ideal A of type 2 which satisfies the condition (9) is a positive implicative weak interior ideal of type 3.

The following example shows that any positive implicative weak interior ideal of type 3 is not a positive implicative weak interior ideal of type 2:

Example 4.35

Consider the BCK-algebra X in Example 4.33. Then the set A:={0,1,2} is a positive implicative weak interior ideal of type 3 in (X,) but it is not a positive implicative weak interior ideal of type 2 since ((3)3)0=0A and (30)=0A but 3(0)=3A.

We establish the relationship between weak interior ideal and positive implicative weak interior ideal of type 1, type 2, and type 3.

Theorem 4.36.

In an interior BCK-algebra, every positive implicative weak interior ideal of type 1 is a weak interior ideal.

Proof.

Let A be a positive implicative weak interior ideal of type 1 in an interior BCK-algebra (X,). If we take z=0 in (29) and use (2), then (x)y=((x)y)0A and (y)=(y0)A which imply that x=x0A. Hence A is a weak interior ideal in (X,).

The converse in Theorem 4.36 is not true in general as shown in the next example.

Example 4.37

Consider the BCK-algebra X in Example 3.20. Define a mapping :XX by (0)=(3)=0 and (1)=(2)=1. Then (X,) is an interior BCK-algebra and A:={0,3} is a weak interior ideal which is not a positive implicative weak interior ideal of type 1 since ((2)1)1=0A,(11)=0A but 21=1A.

Theorem 4.38.

In an interior BCK-algebra, every positive implicative weak interior ideal of type 2 is a weak interior ideal.

Proof.

Let A be a positive implicative weak interior ideal of type 2 in an interior BCK-algebra (X,). If we take z=0 in (30), then (x)y=((x)y)0A and (y)=(y0)A which imply from (2), Proposition 3.13(i) and (30) that x=x0=x(0)A. Hence A is a weak interior ideal in (X,).

The converse in Theorem 4.38 is not true in general as shown in the next example.

Example 4.39

The weak interior ideal A:={0,3} in Example 4.37 is not a positive implicative weak interior ideal of type 2 since ((2)1)1=0A,(11)=0 A but 2(1)=1A.

Theorem 4.40.

In an interior BCK-algebra, every positive implicative interior ideal is a positive implicative weak interior ideal of type 3.

Proof.

Let A be a positive implicative interior ideal in an interior BCK-algebra (X,). Let x,y,zX be such that ((x)y)zA and (yz)A. Then yzA by (21). Since A is a positive implicative ideal of X, it follows from (11) that (x)zA. Therefore A is a positive implicative weak interior ideal of type 3 in (X,).

Corollary 4.41.

Inaninterior BCK-algebra, every positive implicative interior ideal is a weak interior ideal.

Theorem 4.42.

The intersectionofall positive implicative weak interior ideals oftype 1 (respectively, type 2 and type 3) in an interior BCK-algebra (X,) is also a positive implicative weak interior ideal of type 1 (resp., type 2 and type 3) in (X,).

Proof.

Let {AiiΛ} be the set of all positive implicative weak interior ideals of type 1 in an interior BCK-algebra (X,). It is clear that 0iΛAi. Let x,y,zX be such that ((x)y)ziΛAi and (yz)iΛAi. Then ((x)y)zAi and (yz)Ai for all iΛ. Since Ai is a positive implicative weak interior ideal of type 1, it follows that xzAi all iΛ. Thus xziΛAi. Therefore iΛAi is a positive implicative weak interior ideal of type 1 in (X,).

5. CONCLUSIONS

In this paper, we introduce the notion of interior BCK/BCI-algebras, positive implicative interior BCK-algebras, (weak) interior ideals, positive implicative interior ideals, a positive implicative weak interior ideal of type 1, type 2, and type 3, and present some properties and examples related to them. After investigating some results concerning the interior BCK/BCI-algebra, our study has focused on the relationship between bounded BCK-algebras and interior BCK-algebras. We have studied interior ideals, weak interior ideals, and positive implicative interior ideals and have looked for conditions under which a weak interior ideal can be an interior ideal and conditions under which an interior ideal can be a positive implicative interior ideal. Finally, we consider the relationship between type 1, type 2, and type 3 on positive implicative weak interior ideals.

Our future work will include new results regarding the different kinds of interior BCK-algebras and interior ideas. In particular, we will investigate whether interior BCK-algebras have some properties such as commutative, (positive) implicative, and quasi-commutative or not. Moreover, for interior ideals, we will investigate the maximal, (positive) implicative, commutative, prime, and irreducible properties.

COMPLIANCE WITH ETHICAL STANDARDS

Ethical approval: This article does not contain any studies with human participants or animals performed by the author.

Informed consent: Informed consent was obtained from all individual participants included in the study.

CONFLICT OF INTEREST

The authors declare they have no conflicts of interest.

AUTHORS’ CONTRIBUTIONS

All authors contributed equally and significantly to the study and preparation of the manuscript. They have read and approved the final article.

ACKNOWLEDGMENTS

The authors wish to thank the anonymous reviewers for their valuable suggestions.

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Journal
International Journal of Computational Intelligence Systems
Volume-Issue
14 - 1
Pages
1923 - 1933
Publication Date
2021/07/01
ISSN (Online)
1875-6883
ISSN (Print)
1875-6891
DOI
10.2991/ijcis.d.210622.002How to use a DOI?
Copyright
© 2021 The Authors. Published by Atlantis Press B.V.
Open Access
This is an open access article distributed under the CC BY-NC 4.0 license (http://creativecommons.org/licenses/by-nc/4.0/).

Cite this article

TY  - JOUR
AU  - Sun Shin Ahn
AU  - Hashem Bordbar
AU  - Young Bae Jun
PY  - 2021
DA  - 2021/07/01
TI  - Interior BCK/BCI-Algebras
JO  - International Journal of Computational Intelligence Systems
SP  - 1923
EP  - 1933
VL  - 14
IS  - 1
SN  - 1875-6883
UR  - https://doi.org/10.2991/ijcis.d.210622.002
DO  - 10.2991/ijcis.d.210622.002
ID  - Ahn2021
ER  -